硬件无论如何狂奔，最终都要落回到与人的连接上。
For 4 points, that is (1/2)3=1/8(1/2)^3 = 1/8(1/2)3=1/8, the same 12.5% we measured earlier. There is one such event for each of the NNN points, so we have NNN events each with probability 1/2N−11/2^{N-1}1/2N−1.
table to perform the having clause. This means that our single for-loop won’t cut it anymore. Also on a side note: Did，更多细节参见体育直播
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